Published 2026-08-26
Chapter: Simple Equations

Simple Equations - Formulation and solving of simple linear equations

Today, we are going to explore Simple Equations from your NCERT Class 7 syllabus.

Have you ever wondered how detectives solve mysteries by finding missing clues? In mathematics, an equation is just like a detective puzzle where we need to find a missing number!

By the end of this lesson, you will be able to:

  1. Understand what an equation is.
  2. Turn real-world word problems into mathematical equations (Formulation).
  3. Find the value of the unknown variable (Solving).

Let's dive in!


1. The Big Picture: The Weighing Balance Analogy

Imagine a traditional vegetable vendor's weighing scale (Tarazu).

     [ Left Pan ]  === (Equal Balance) ===  [ Right Pan ]
  • For the scale to remain balanced, the weight on the Left-Hand Side (LHS) must be equal to the weight on the Right-Hand Side (RHS).
  • If you add a 1 kg1\text{ kg} weight to the left pan, the balance tips! To bring it back to balance, you must add 1 kg1\text{ kg} to the right pan too.
  • Similarly, if you remove weight from one side, you must remove the exact same weight from the other side.

An equation works on the exact same logic! An equation is simply a statement that shows two mathematical expressions are equal, joined by an equal sign (==).


2. What Makes Up an Equation?

Before we start building equations, let's learn the basic building blocks:

  1. Variable: A letter (like x,y,z,m,px, y, z, m, p) that represents an unknown number. Its value can change (vary).
  2. Constant: A fixed numerical value that never changes (like 5,12,−35, 12, -3).
  3. Algebraic Expression: A combination of variables, constants, and operations (+,−,×,÷+, -, \times, \div).
    • Example: 2x+32x + 3
  4. Equation: When we set an expression equal to a value or another expression using an equal sign (==).
    • Example: 2x+3=112x + 3 = 11

💡 Teacher's Note: An equation MUST always have an equal sign (==). Without an equal sign, 2x+32x + 3 is just an expression, not an equation!


3. Step 1: Formulating Equations from Word Statements

Formulating an equation means converting everyday English sentences into mathematical statements.

Simple Rules to Translate Words into Math:

  • "Sum of..." or "added to" →+\rightarrow \mathbf{+}
  • "Difference of..." or "subtracted from" →−\rightarrow \mathbf{-}
  • "Times..." or "product of" →×\rightarrow \mathbf{\times}
  • "Divided by..." or "one-third of" →÷\rightarrow \mathbf{\div}
  • "Is...", "gives...", or "results in..." →=\rightarrow \mathbf{=}

Let's See Some Examples:

Word StatementStep-by-Step TranslationAlgebraic Equation
1. The sum of a number xx and 44 is 1212.Add 44 to xx to get 1212.x+4=12x + 4 = 12
2. 77 times a number mm minus 33 gives 1818.Multiply mm by 77, then subtract 33.7m−3=187m - 3 = 18
3. One-fifth of a number yy is 66.Divide yy by 55 to equal 66.y5=6\frac{y}{5} = 6

4. Step 2: Solving Simple Equations

Solving an equation means finding the exact numerical value of the variable that makes the Left Hand Side (LHS) = Right Hand Side (RHS). This value is called the solution or root of the equation.

There are two primary methods to solve an equation:

Method A: The Balancing Method

Just like a weighing scale, whatever operation you perform on the Left-Hand Side, you must perform the exact same operation on the Right-Hand Side.

Example: Solve x+5=12x + 5 = 12

  • Goal: Keep xx alone on the LHS.
  • Problem: There is an extra +5+ 5 attached to xx.
  • Action: Subtract 55 from both sides. x+5−5=12−5x + 5 - 5 = 12 - 5 x=7x = 7

Method B: The Transposition Method (Fast & Easy!)

Transposition means moving a term from one side of the equal sign (==) to the other side. When a term crosses the equal sign bridge, its sign flips to its opposite operation:

  • Plus (++) becomes Minus (−-)
  • Minus (−-) becomes Plus (++)
  • Multiplication (×\times) becomes Division (÷\div)
  • Division (÷\div) becomes Multiplication (×\times)

Let's walk through an example using Transposition:

Solve: 3y−7=143y - 7 = 14

  • Step 1: Move the constant term (−7-7) across the equal sign. Since it is −7-7, moving it to the RHS changes it to +7+7. 3y=14+73y = 14 + 7 3y=213y = 21

  • Step 2: Move the multiplier (33) across the equal sign. Since 33 is multiplied by yy, moving it to the RHS changes it to division by 33. y=213y = \frac{21}{3} y=7y = 7

Answer: y=7y = 7


Practice Corner: Guided Questions with Detailed Solutions

Now, let's put our learning into action with 3 classic NCERT-style practice questions!


Question 1: Formulation & Solving

Statement: "If you subtract 66 from 66 times a number nn, you get 6060." Task: Formulate the equation and solve for nn.

Solution:

  • Step 1: Formulate the equation.

    • 66 times a number nn = 6n6n
    • Subtracting 66 from 6n6n = 6n−66n - 6
    • The result is 6060, so set it equal to 6060: 6n−6=60\mathbf{6n - 6 = 60}
  • Step 2: Solve the equation using Transposition.

    • Move −6-6 to the RHS (it becomes +6+6): 6n=60+66n = 60 + 6 6n=666n = 66
    • Move 66 (multiplier) to the RHS (it becomes a divisor): n=666n = \frac{66}{6} n=11n = 11

Final Answer: The equation is 6n−6=606n - 6 = 60, and the value of nn is 1111.


Question 2: Solving Equations with Brackets

Solve the equation: 4(m+3)=204(m + 3) = 20

Solution:

  • Step 1: Simplify or transpose the multiplier outside the bracket. The number 44 is multiplied with the entire bracket (m+3)(m + 3). Move 44 to the RHS as a division: m+3=204m + 3 = \frac{20}{4} m+3=5m + 3 = 5

  • Step 2: Isolate the variable mm. Move +3+3 to the RHS (it becomes −3-3): m=5−3m = 5 - 3 m=2m = 2

  • Step 3: Check your answer (Verification). Substitute m=2m = 2 back into the LHS: LHS=4(2+3)=4(5)=20=RHS\text{LHS} = 4(2 + 3) = 4(5) = 20 = \text{RHS} Since LHS=RHS\text{LHS} = \text{RHS}, our answer is correct!

Final Answer: m=2m = 2


Question 3: Real-World Word Problem

Problem: Rohan's father is 4545 years old. He is 33 years older than three times Rohan's age. Find Rohan's age.

Solution:

  • Step 1: Define the unknown variable. Let Rohan's age be xx years.

  • Step 2: Formulate the equation based on the condition.

    • Three times Rohan's age = 3x3x
    • Father is 33 years older than 3x3x = 3x+33x + 3
    • Father's actual age = 4545
    • Setting up the equation: 3x+3=45\mathbf{3x + 3 = 45}
  • Step 3: Solve the equation.

    • Transpose +3+3 to the RHS: 3x=45−33x = 45 - 3 3x=423x = 42
    • Transpose 33 to the RHS: x=423x = \frac{42}{3} x=14x = 14

Final Answer: Rohan's age is 1414 years.


Summary Checklist for Revision

  1. Equation: LHS = RHS statement containing a variable.
  2. Formulation: Read carefully →\rightarrow identify unknown as variable →\rightarrow translate words into operations.
  3. Transposition Rules:
    • +→−+ \rightarrow -
    • −→+- \rightarrow +
    • ×→÷\times \rightarrow \div
    • ÷→×\div \rightarrow \times

Keep practicing, stay curious, and remember: math is just a game of rules! You've got this!

Common Student Mistakes to Avoid

  1. Sign Errors in Algebraic Calculations: Mistakes in distributing negative signs across brackets or when transferring terms across the equals sign.
  2. Formula Misapplication: Memorizing formulas without checking required units or conditions (e.g. using diameter instead of radius).
  3. Skipping Intermediate Steps: Jumping directly to final numerical answers without showing step-by-step mathematical working, leading to partial credit loss in board exams.
  4. Incorrect Unit Conversions: Forgetting to convert parameters into uniform SI units (e.g., cm to meters or minutes to seconds) before computing.

Exam Preparation & Frequently Asked Questions (FAQ)

Q1. How should I revise Simple Equations for the Class 7 Mathematics examination?

Focus on mastering core textbook definitions, practicing 3-4 numerical problems daily with pen and paper, and reviewing previous year CBSE/NCERT board exam questions.

Q2. What are the key concepts that carry maximum marks in this chapter?

Pay special attention to core definitions, step-by-step derivations, solved textbook examples, and practical real-world applications outlined in your NCERT curriculum.

Q3. How can I avoid losing marks in long answer questions?

Always structure your answers with clear subheadings, write step-by-step working for numerical problems, state given values clearly, and highlight your final answers with correct SI units.

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